4x^2-8x=-16/3

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Solution for 4x^2-8x=-16/3 equation: 


x in (-oo:+oo)

4*x^2-(8*x) = -16/3 // + -16/3

4*x^2-(8*x)-(-16/3) = 0

4*x^2-8*x+16/3 = 0

4*x^2-8*x+16/3 = 0

DELTA = (-8)^2-(4*4*16/3)

DELTA = -64/3

DELTA < 0

x belongs to the empty set

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